A and B are at the starting and finishing points respectively of a 12-km cross-country route.

At 0700, Chad jogs from A towards B at 6km/h.

At 0730, Wei Liang jogs from B towards A at 3km/h.

(i) What time will Chad and Wei Liang meet?

(ii) How far would Chad have jogged when he meets Wei Liang?

Let the distance of 12-km be "a".

Chad 0700 - 0730:

T –> 0.5h

S –> 6km/h

D –> 0.5 x 3 = 3km

Distance between Chad and Wei Liang at 0730 –> (a - 3)km

Total speed of Chad and Wei Liang –> 6km/h + 3km/h = 9km/h

Time taken to meet –> (a-3)/9 h

Find "a":

a -3 / 9

a = 9+3

a = 12

Time taken to meet –> (12-3)/9 = 9/9 = 1h

0730 –1hour–> 0830

Distance Chad jogged:

T –> 0.5 + 1 = 1.5h

Speed –> 6km/h

Distance –> 1.5 x 6 = 9km

(i) Chad will meet Wei Liang at 0830

(ii) Chad would have jogged 9km when he met Wei Liang.

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